The table below was created using the Excel Spreadsheet. Below the table is a list by column of explanations of the mathematics used to produce the specific column's results. The Excel formula is also given.
Noon Observation Project Worksheet | |||||||||
Site Name | City | State | Country | latitude | shadow length | angle | north/south distance | circumference estimate | % error |
Lindfield Primary School | Sydney | New South Wales | Australia | -33.8 | 62.6 | 122.0489 | 0 | 40008 km | Deviation |
Axtell Park Middle School | Sioux Falls | South Dakota | USA | 43.5 | 93.1 | 47.0433 | 8590.5809 | 41231.69474 | 3.05863 |
Arundel High School | Gambrills | Maryland | USA | 39.07 | 79.9 | 51.3723 | 8098.26171 | 41249.47976 | 3.10308 |
Canterbury High School | Canterbury | Kent | England | 51.2 | 129.47 | 37.67792 | 9446.305 | 40306.13856 | 0.7452 |
Central High School | Champaign | Illinois | USA | 40.1 | 83.3 | 50.20277 | 8212.7287 | 41151.57112 | 2.85836 |
Faubion Middle School | McKinney | Texas | USA | 33.2 | 62 | 58.19874 | 7445.911 | 41981.5221 | 4.93282 |
James M. Bennett High | Salisbury | Maryland | USA | 38.33 | 77.7 | 52.15001 | 8016.02329 | 41284.87525 | 3.19155 |
La Grange Highlands Elem. S. | La Grange | Illinois | U.S.A. | 41.48 | 84.4 | 49.83268 | 8366.09224 | 41705.19827 | 4.24215 |
Ludwig-Uhland Gymnasium | Kircheim | Württemberg Baden | Germany | 48.64 | 114 | 41.25342 | 9161.80452 | 40822.19021 | 2.03507 |
Manasquan High School | Manasquan | New Jersey | USA | 40.13 | 80.5 | 51.16307 | 8216.06269 | 41725.99098 | 4.29412 |
Mott Middle College High | Flint | Michigan | USA | 43 | 93.1 | 47.0433 | 8535.0144 | 40964.99555 | 2.39201 |
North East High 2 | North East | Maryland | USA | 39.6 | 83.5 | 50.13518 | 8157.1622 | 40834.7289 | 2.06641 |
North East High School | North East | Maryland | USA | 39.6 | 82.5 | 50.47446 | 8157.1622 | 41028.29245 | 2.55022 |
P.S. 16 | Bronx | New York | USA | 40.9 | 80.2 | 51.26753 | 8301.6351 | 42222.79878 | 5.53589 |
St. Andrew Catholic School | Fort Worth | Texas | USA | 32.7 | 62.8 | 57.86881 | 7390.3445 | 41454.02219 | 3.61433 |
University of Puerto Rico | San Juan | Puerto Rico | USA | 18.45 | 33.7 | 71.37481 | 5806.69925 | 41252.05923 | 3.10953 |
Wanniassa Hills Primary School | Canberra | Australia Capital T. | Australia | -35.17 | 71.5 | 125.5674 | 152.25221 | 15578.07414 | -61.0626 |
Werner-von-Siemens-Realschule | Erlangen | Bavaria | Germany | 49.6 | Rain | Rain | Rain | Rain | Rain |
Williamsport High School | Williamsport | Maryland | USA | 39.6 | 78.6 | 51.82984 | 8157.1622 | 41820.22956 | 4.52967 |
Hazelton Elementary School | Stockdale | California | USA | 37.5 | 69.75 | 55.10166 | 7923.7829 | 42609.08144 | 6.5014 |
Tucson Hebrew Academy | Tucson | Arizona | USA | 32.2 | 61.9 | 58.24015 | 7334.778 | 41381.76924 | 3.43374 |
Explanation of the Excel Spreadsheet Formula
Column by Column
by
Kenneth Cole, Mathematics Teacher
Faubion Middle School
March 31, 1997
Note: In the formula below, the green highlighted
variables labeled as column 1,
column 7, etc., in Excel as in
most spreadsheets are replaced by the actual cell name, i.e., use for example, column 7. If the column of the cell was
labeled "G" and the
row of the cell is labeled "6" instead of column7, the formula would have an entry of "G6".
So, the formula in Column 7 below which is written, =90-ATAN[(column 6)/100]*57.3*SIGN(column 5), in Excel would actually be written with the cell
names for row 4, =90-ATAN[(F4)/100]*57.3*SIGN(E4).
One further note: One modification which was made in the formulae written below is the use
of hierarchical grouping symbols which Excel does not use. Thus, the formula given in the
preceeding paragraph whould be written: =90-ATAN((F4)/100)*57.3*SIGN(E4)
in Excel. In other words, the {x[y(x+y)]} grouping symbols are written (x(y(x+y))) in Excel.
Column 1: Site Name: School Name
Column 2: City
Column 3: State
Column 4: Country
Column 5: Latitudepositive value indicates northern latitude--negative value indicates southern latitude
Column 6: Length of shadow of a meter stick at local noon time
Column 7: The angle of the Sun at noonThis is found by dividing the height of the stick (100 centimeters) by the length of the shadow in centimeters, which yields the tangent ratio of the angle of the shadow. Then to find the measure of the angle of the shadow in radians, you take the arc tangent of that ratio. Then, to convert from radians to degrees, you multiply by 57.3, which is the number of degrees in a radian. Next, to find the angle of the Sun, you subtract your answer from 90°. The last thing we do is multiply by the sign of the latitude to insure that the sites from the southern latitudes show a opposite direction from the sites in the northern latitudes for distance purposes later.
The Excel formula which we use is:
=90-ATAN[(column 6)/100]*57.3*SIGN(column 5)
Column 8: The North-South
DistanceTo understand what we are doing here, just think about why we take our
readings at our local noon time. Imagine that we are lining up all of our schools at the
same place on the globe, longitudinally, say at the Prime Meridian. The only distance
between the schools would be the north-south distance.
Which school is the starting place? We have to choose. Since Lindfield Primary had a very
accurate measure of the angle of the Sun, we choose to start there. This is somewhat
unfortunate for Wanniassa Hills Primary because Lindfield is very close in distance, north
to south that is. This magnifies any error which both sites make. That is why the
deviation at Waniassa Hills' site seems so large compared to the other sites. All it
really means is that we are looking at a much smaller piece which makes our measurements
seem less accurate.
It might compare with trying to find the circumference of a basketball by bending a one
centimeter long wire and sketching the circumference of the basketball from that arc. Then
bending a 20 centimeter long wire and using that arc to sketch the shape of the circle for
the circumference of the ball.
Now to find the circumference, we need to know how far in degrees our sites are from
Lindfield. We find that distance by subtracting current site's latitude, in degrees, from
-33.8°, which is the latitude of Lindfield. To find the distance regardless of the
direction, we use the absolute value of that number of difference in degrees. To convert
the distance from degrees to kilometers, we then multiply by 111.133 the number of
kilometers in a degree on the north-south circumference of the Earth. You can find this
number by dividing the actual circumference, 40008 km by 360.
The Excel formula which we use is:
=ABS(-33.8-column 5) *111.133
Column 9: Circumference EstimateOnce you know the distance between the two sites and the difference between the angle of the Sun at the two sites, you simply divide the distance by the angular difference which gives you the distance of a one degree arc. You might remember that the degree measure of an arc is the same as the degree of angle which defines it. Therefore dividing the number by itself yields one degree. Now to find the circumference estimate, multiply that one degree length by 360.
The Excel formula which we use is:
=ABS[(column 8*360)/(122.04893-column 7)]
Column 10: The Percent of Deviation from the Actual CircumferenceTo find this number we subtract the actual circumference from our estimate in column 9, divide the answer by the actual circumference, 40008 km. To convert this ratio to a percent, we multiply by 100.
The Excel formula which we use is:
=[(column 940008)/40008]*100
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Last Updated on 4/9/97
By Kenneth Cole
Email: kcole@isource.net