Acid-Base Equilibria

46) [ClCH₂COOH] = 0.100 M          %ion = 11.0%             

            ClCH₂COOH(aq) H⁺(aq) + ClCH₂COO^-(aq)

      [ ]_i         0.100                            0                   0

      [ ]_c          -0.011                       +0.011          +0.011

      [ ]_e           0.100-0.011               0.011            0.011

      %ion = [H⁺]/[ClCH₂COOH] x 100%

      [H⁺]/[ClCH₂COOH] = 0.110

      [H⁺] = 0.110 x [ClCH₂COOH] = 0.110 x 0.100 M = 0.011 M

      [H⁺] = [ClCH₂COO^-] = 0.011 M

      [ClCH₂COOH]_eq = 0.100 M - 0.011 M = 0.089 M

      K_a = [H⁺] x [ClCH₂COO^-]/[ClCH₂COOH]

      K_a = 0.011 x 0.011/0.089 = 1.4 x 10^-3