48) (a) m = 2.87 g CxHyOz m = 6.32 mg CO2 m = 2.58 mg H2
m
= 6.32 mg CO2 * 1 mol CO2/44.01 g CO2
* 1 g/103 mg * 1 mol C/1 mol CO2
* 12.01 g C/1 mol C = 1.72 x 10-3 g
C
n = 1.44 x 10-4 mol C
m
= 2.58 mg H2O * 1 mol H2O/18.02 g H2O
* 1 g/103 mg * 2 mol H/1 mol H2O
* 1.01 g H/1 mol H = 2.89 x 10-4 g H
n = 2.86 x 10-4 mol H
m = 2.78 mg x 1 g/103 mg - 1.72
x 10-3 g C - 2.89 x 10-4 g H = 7.71 x 10-4
g O
n = 7.71 x 10-4 g O * 1 mol O/16.00 g O = 4.82 x 10-5
mol O
C0.000144H0.000286O0.0000482 ===> C2.99H5.93O ===> C3H6O