99) l = w = h = 1.000 cm D = 10.49 g/cm3
(a) D = M/V
M
= 10.49 g/cm3 * 1.000 cm * 1.000 cm * 1.000
cm = 10.49 g Ag
n
= 10.49 g Ag * 1 mol Ag/107.87 g Ag * 6.02 x 1023
Ag atoms/1 mol Ag = 5.85 x 1022 Ag atoms
(b) V% = VAg/Vcube * 100%
V% = 0.74 * 1.000 cm3 = 0.74 cm3
VAg = 0.74 cm3/(5.85 x 1022 Ag atoms) = 1.3 x 10-23 cm3/Ag atom
(c) V = 4/3 * 3.14 * r3
1.3 x 10-23 cm3 = 4/3 * 3.14 * r3
r
= 1.5 x 10-8 cm * 1 m/102 cm * 1
Å/10-10 m = 1.5 Å