Chemical Equilibrium

12) K_eq = 1.3 x 10^-2          T = 1000 K

      2NO(g) + Br₂(g) 2NOBr(g)

      (a) 2NOBr(g) 2NO(g) + Br₂(g)

            K_eq' = 1/K_eq = (1.3 x 10^-2)^-1 = 77

      (b) Because K_eq' >>> 1, the equilibrium favors NO(g) and Br₂(g).