Chemical Equilibrium

22)  P_PCl3 = 0.124 atm          P_Cl2 = 0.157 atm          P_PCl5 = 1.30 atm          T = 450 K

       PCl₃(g) + Cl₂(g) PCl₅(g)

      
       (a) K_eq = P_PCl5/(P_PCl3 x P_Cl2) = 1.30/(0.124 x 0.157) = 66.8

       (b) Because K_eq >>> 1, the formation of PCl₅ is favored over the reactants.