Chemical Kinetics

 42) (a) E_a = 160.0 kJ/mol          T = 500 K          R = 8.31 J/mol•K

             f = e^-Ea/RT

             E_a/RT = 160.0 kJ/mol/(8.31 J/mol•K x 1 kJ/10³ J x 500 K) = 38.5

             f = e^-38.5 = 2 x 10^-17

       (b) T = 510 K

             E_a/RT = 160.0 kJ/mol/(8.31 J/mol•K x 1 kJ/10³ J x 510 K) = 37.8

             f = e^-37.8 = 4 x 10^-17

             f^₅₁₀/f₅₀₀ = 4 x 10^-17/2 x 10^-17 = 2

             An increase in temperature of 10 K results in twice the number of molecules having this energy.