Chemical Kinetics

 

 76) [NO] = 0.040 M          [O2] = 0.035 M

       Rate = -Δ[NO]/Δ t = -9.3 x 10-5 M/s

       2NO(g) + O2(g) 2NO2(g)

       (a) Rate = -Δ[O2]/Δ t = -1/2Δ[NO]/Δ t = -1/2 x -9.3 x 10-5 M/s = 4.6 x 10-5 M/s

 

       (b) Rate = k[NO]2[O2]

             -9.3 x 10-5 M/s = k x (0.040 M)2 x 0.035 M

             k = 1.7 M-2s-1

           

       (c) M-2s-1

 

       (d) Rate = k[NO]2[O2]

            -9.3 x 10-5 M/s = 1.7 M-2s-1 x (0.040 M)2 x 0.035 M

            -3.1 x 10-4 M/s = 1.7 M-2s-1 x (0.040 M x 1.8)2 x 0.035 M

            Rate2/Rate1 = -3.1 x 10-4 M/s/-9.3 x 10-5 M/s = 3.3

            

            Rate2 increases by a factor of 3.3 (1.82) when NO increases by a factor of 1.8.

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