Electrochemistry

 80) (a) I = 5.25 A

            Δt = 2.50 days x 24 hr/1 day x 3600 s/1 hr = 2.16 x 10⁵ s

            Mg²⁺(l) + 2e^- Mg(s)

            m_Mg = 5.25 C/s x 2.16 x 10⁵ s x 1 mol e^-/96500 C x 1 mol Mg/2 mol e^- x 24.30 g Mg/1 mol Mg

            m_Mg = 143 g Mg

       (b) m_Mg = 10.00 g Mg          I = 3.50 A

            Q = I/Δt

            Δt = Q/I

            Δt = (10.00 g Mg x 1 mol Mg/24.30 g Mg x 2 mol e^-/1 mol Mg x 96500 C/1 mol e^-)/(3.50 C/s x 60 s/min)

            Δt = 378 min