32) V = 456 mL m = 3.18 g C3H8 R = 0.0821 L•atm•mol-1•K-1 T = 23°C
(a) PV = nRT = 3.18 g C3H8
* 1 mol C3H8/44.11 g C3H8
* 0.0821 L•atm•mol-1•K-1
* 296 K/(456 mL * 1 L/103 mL)
P = 3.84 atm
(b) V1 = 456 mL V2 = ?
P1 = 3.84 atm P2 = 1.00 atm
T1 = 296 K T2 = 273 K
P1V1/T1 = P2V2/T2
V2 = 3.84 atm * 456 mL * 1 L/103 mL
* 273 K/296 K/1.00 atm = 1.61 L
(c) V1 = 456 mL V2 = 456 mL
P1 = 3.84 atm P2 = ?
T1 = 296 K T2 = 130° F
P1/ T1 = P2/T2
P2 = 3.84 atm * 5/9 * ((130-32) + 273)/296 K = 4.25
atm