Properties of Solutions

24) (a)  n = 0.045 mol I₂

             m = 115 g CCl₄

             I₂(s) I₂(l)

             m% = m_iodine/m_sol'n x 100%

             m_iodine = 0.045 mol I₂ x 253.80 g I₂/1 mol I₂ = 11 g I₂

             m_sol'n = 11 g I₂ + 115 g CCl₄ = 126 g sol'n

             m% = 11 g/126 g x 100% = 8.7 % I₂

      (b)   0.0079 g Sr²⁺/kg

             ppm = m_solvent/m_sol'n x 10⁶

             ppm = 0.0079 g Sr²⁺/10³ g x 10⁶ = 7.9 ppm Sr²⁺