Properties of Solutions

40)  D = 1.42 g/mL

       [HNO₃] = 16 M

      
       HNO₃(aq)  H⁺(aq) + NO₃^-(aq)

       m% = m_solute/m_sol'n x 100%

       Assume V = 1.00 L

       D = M/V

       M = D x V = 1.42 g/mL x 1.00 L x 10³ mL/L = 1420 g sol'n

       [HNO₃] = n/V

       n = [HNO₃] x V = 16 mol HNO₃/L x 1.00 L = 16 mol HNO₃

       m = 16 mol HNO₃ x 63.02 g HNO₃/1 mol HNO₃ = 1.0 x 10³ g HNO₃

       m% = 1.0 x 10³ g HNO₃/1420 g sol'n x 100% = 70.% HNO₃