34) The reason for each of the choices below is the same. The more readily a substance is oxidized (the more negative the E°red or the more positive the E°ox ) the stronger the reducing agent.
(a) Fe2+(aq) + 2e- Fe(s) E°red = -0.440 V
Mg2+(aq) + 2e- Mg(s) E°red = -2.37 V
Mg(s) is the better reducing agent.
(b) Ca2+(aq) + 2e- Ca(s) E°red = -2.87 V
Al3+(aq) + 3e- Al(s) E°red = -1.66 V
Ca(s) is the better reducing agent.
(c) 2H+(aq) + 2e- H2(g) E°red = 0.000 V
S(s) + 2H+(aq) + 2e- H2S(g) E°red = +0.141 V
H2(g) is the better reducing agent.
(d) HSO4- (aq) + 3H+ + 2e- H2SO3(aq) + H2O(l) E°red = +0.17 V
2CO2(g) + 2H+(aq) + 2e- H2C2O4(aq) E°red = -0.49 V
H2C2O4(aq) is the better reducing agent.