Practice Problem #1: |
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a) What is the empirical (simplest) formula of the caffeine? b) What is the chemical formula of caffeine? |
1) Get from percentages into units of mass (grams). 2) Use information from the periodic table to convert grams into the number of moles. 3) Do a mole-to-mole comparison so we can get the ratio of carbon to oxygen to hydrogen. 4) Once we have a ratio of each of these, we can determine the formula for the compound. 5) Compare the molar mass of the formula to the given molar mass of the compound. If it's the same, we're done. If it's different, we'll have to adjust things.
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1) Get from percentages into units of mass (grams)
Using the percentages given: | With 100 grams of the compound: |
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49.5% carbon | 49.5 grams carbon |
5.2% hydrogen | 5.2 grams hydrogen |
28.8% nitrogen | 28.8 grams nitrogen |
16.5% oxygen | 16.5 grams oxygen |
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100% total | 100 grams total |
2) Use information from the periodic table to convert grams into the number of moles
Using the periodic table, we can get the following information about the molar masses of carbon, hydrogen, nitrogen and oxygen:
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Carbon: 1 mole carbon 49.5grams carbonx ------------------ = 4.12 moles carbon 12.01grams carbonHydrogen: 1 mole hydrogen 5.2grams hydrogenx ------------------ = 5.15 moles hydrogen 1.01grams hydrogenNitrogen: 1 mole nitrogen 28.8grams oxygenx ------------------ = 2.06 moles nitrogen 14.01grams nitrogenOxygen: 1 mole oxygen 16.5grams oxygenx ------------------ = 1.03 moles oxygen 16.00grams oxygen
3) Do a mole-to-mole comparison so we can get the ratio of carbon to oxygen to hydrogen
Just divide by the smallest number.
In this case, we see that oxygen has the smallest number of moles: 1.03
So divide all the numbers by 1.03:
Carbon: 4.12 moles carbon / 1.03 = 4.0 moles carbon Hydrogen: 5.15 moles hydrogen / 1.03 = 5.0 moles hydrogen Nitrogen: 2.06 moles nitrogen / 1.03 = 2.0 moles nitrogen Oxygen: 1.03 moles oxygen / 1.03 = 1.0 moles oxygen
4) Once we have a ratio of each of these, we can determine the formula for the compound.
Try putting the number of moles as subscripts for each element:
C4H5N2O
We have no "halves" of moles, so that formula is fine.
Let's determine the molar mass.
[Note: If you're unsure how to calculate molar mass, check out the Moles and Molar Mass Tutorial.]
Carbon: 12.01 grams carbon 4 moles carbon x ------------------ = 48.04 grams carbon 1 mole carbon Hydrogen 1.01 grams hydrogen 5 moles hydrogen x ------------------- = 5.05 grams hydrogen 1 mole hydrogen Nitrogen 14.01 grams hydrogen 2 moles hydrogen x ------------------- = 28.02 grams nitrogen 1 mole nitrogen Oxygen 16.00 grams oxygen 1 mole oxygen x ------------------ = 16.00 grams oxygen 1 mole oxygenAdd up the masses of carbon, hydrogen and oxygen to get the molar mass of C4H5N2O:
Compare this to what was given at the very beginning of the problem:
The molar mass of caffeine is approximately 194 grams per mole. |
Whoops! We have a compound with a mass of 97.11 grams/mole.
This means that C4H5N2O is the empirical formula of the compound.
empirical formula = simplest formula
Let's divide the molar mass of caffeine by the molar mass of C4H5N2O:
194 grams caffeine / 97.11 grams C4H5N2O = 2.0
OK, so we know that the molar mass of caffeine is TWICE as much as the molar mass of C4H5N2O.
Multiply all those subscripts by 2:
C8H10N4O2
The molar mass of C8H10N4O2 is 194.22 grams/mole. That's pretty close to the number specified by the problem.
So here are our answers:
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