Dynamics of Circular Motion
Physics: Chapter 5
- Definitions
- Uniform Circular Motion: motion of an object traveling at a constant speed on a
circular path
- Period (T): time need for one revolution of circle
- Speed (v)
- Circumference is distance (2pr)
- r measured at right angle to rotation
- Period (T) is time
- v = (2pr)/T
- unit: m/s
- Centripetal Acceleration (ac)
- Depends on v and r
- Use similar triangles to determine
- Dv/v = (vDt)/r
- Solve for acceleration Dv/Dt
- Magnitude: ac = v2/r
- units: m/s2
- Direction: toward center of circle, continuously changing
- Centripetal Force
- Magnitude: F = ma = mv2/r
- Direction: toward center of circle, continuously changing
- Banked Curves: Analysis:
- Fc determined by r of curve and v of car
- Fc also equal to component of FN toward center of curve
- That component is opposite q, so multiply FN by sine
- Vertical component of FN balances weight of car (mg) [(FN cos q) = mg]
- Bank Angle Solution
- Fc = FN sin q = mv2/r
- Divide by weight
- (FN sin q)/(FN cos q) = (mv2/r)/mg
- sin/cos = tan
- tan q = v2/rg
- The Motion of Satellites
- Kepler's First Law
- The orbit of each planet is an ellipse with the sun at one focus
- By determining the curve in one part we can deduce the whole orbit
- Kepler's Second Law
- An imaginary line from the sun to a moving planet sweeps out equal area
in equal times.
- Predict speed of satellites for rendezvous
- Kepler's Third Law
- The ratio of the square of a planet's period to the cube of its average
distance from the sun is a constant.
- Constant is the same for all things orbiting a body
- T2/R3 = k
- Satellites: Orbital Speed
- Fc of satellite:
- Fc is same as force of gravity: G(mME)/r2 (from Newton)
- (r is measure to center of Earth)
- m is mass of satellite
- Fc also is mv2/r
- Use these equations to solve for v
- Set equations equal to each other
- G(mME)/r2 = mv2/r
- Solve for v
- v = GME /r
- Only 1 speed is possible for given r
- Speed is independent of m
- GPS
- Satellites in geosychronous orbit
- v, G, ME known
- Clock in receiver synchronized with satellite
- Each satellite determines value for r
- Intersection of circles is location
- Orbital Period
- v = 2pr/T
- v is also v = GME /r
- Solve these equations for T
- T = 2pr3/2 / GME
- This is Kepler's 3rd law
- Apparent Weightlessness
- Apparent weight is force of one object pushing on another
- If both objects fall (are accelerated) at same speed apparent weight is 0
- Objects in orbit fall to center of Earth at same rate and appear weightless
- Artificial Gravity
- Rotation of space station creates Fc at outer surface of station
- Surface of station pushes person in station with Fc
- This push is perceived as gravity
- Results in apparent weight